c语言:输入一组整数,统计并输出其中的正数的累加和,及负数的个数。答:4,9,-6,8,10,4};int len;int posSum = 0, negCnt = 0;int i;len = 10;for (i=0; i<len; i++) {if (arr[i]>0)posSum += arr[i];if (arr[i]<0)negCnt++;}printf ("正数累加和:%d\n负数个数:%d\n", posSum, negCnt);getch (); /*屏幕暂留*/return 0;} ...