一道类似鸡兔同笼的C语言程序题, n个头和m只脚。请你帮他写个程序计算...答:先输入后输入不一致的问题,是flag没有及时归零导致的。...int dove,rabbit,flag;//flag不要赋值,将=0去掉int head,feet,df,rf;while(scanf("%d %d",&head,&feet),head,feet){flag=0;//循环体内一开始给flag赋值0dove=0;rabbit=0;for(dove=0;(dove<=head)&&(dove<=feet/2)&&(head-...
根据下题编写一个C语言程序 鸡兔同笼,已知鸡兔总头数h,总脚数为f求鸡...答:include <stdio.h> void main(){ int head,feet,chead,rhead,cfeet,rfeet;scanf("%d %d",&head,&feet);for(rhead=0;rhead<=head;rhead++){ chead=head-rhead;cfeet=chead*2;rfeet=rhead*4;if(feet==cfeet+rfeet){ printf("chicken : %d rabbit : %d",chead,rhead);exit(0);...