c++有n个整数,使前面各数顺序向后移m个位置,最后m个数变成前面m个数...答:include <iostream>using namespace std;void Swaping(int,int),Inversion(int[],int,int);int main(){int a[8]={1,2,3,4,5,6,7,8};Inversion(a,8,2);for (int i=0;i<8;i++) cout<<a[i]<<" "; cout<<endl;return 1;}void Swaping(int *a,int *b){*b=(*a)+...