求下列图中函数的微分、谢谢了~~~

Question

如题所述

Answer 1

导数即“微商”，因而先求导 (复合函数求导）
dy/dx=y'=2sin(3x+5)*cos(3x+5)*3
=3*sin2*(3x+5)
=3sin(6x+10)
dy=3sin(6x+10)dx

Answer 2

解：
y=sin²(3x+5)
dy/dx=2sin(3x+5)·[sin(3x+5)] '
=2sin(3x+5)·cos(3x+5)·(3x+5) '
=2sin(3x+5)·cos(3x+5)·3
=3sin(6x+10)
故微分dy=3sin(6x+10)dx本回答被提问者和网友采纳