编写程序,求5个随机数的平均值(使用math类的random()静态方法可以产生一个0-1之间的随机数)

Question

如题所述

Answer 1

public class TestRandom {

public static void main(String[] args) {
int a[] = new int[5];
int i,num=0,sum=0;
System.out.println("100以内的五个随机数为：");
for (i=0;i<5;i++){
num = (int)(Math.random()*100);
a[i]=num;
sum += num;
System.out.print(a[i]+" ");
}
sum = sum/5;
System.out.println("\n平均数为:\n"+sum);

}

}

Answer 2

给一个DELPHI的例子：
unit Unit1;

interface

uses
Windows, Messages, SysUtils, Variants, Classes, Graphics, Controls, Forms,
Dialogs, StdCtrls;

type
TForm1 = class(TForm)
Button1: TButton;
procedure Button1Click(Sender: TObject);
private
{ Private declarations }
public
{ Public declarations }
end;

var
Form1: TForm1;

implementation

{$R *.dfm}
function GetAverageValue:real;
var
a: Array[0..4] of real;
t:real;
i:integer;
begin
Randomize;
for i:=0 to 4 do
begin
a[i]:=random;
t:=t+a[i];
end;
Result:=t/5;
end;

procedure TForm1.Button1Click(Sender: TObject);
begin
Button1.Caption:=floattostr(GetAverageValue);
end;

end.

//在delphi里random()不是math的，是system的。本回答被网友采纳