求导数y=(arctan1/x)^2

Question

求导数y=(arctan1/x)^2

Answer 1

y'=(-2arctan1/x)/x^2*{1/[1+(1/x)^2]}

=(-2arctan1/x)/x^2*x^2/(x^2+1)

=-(2arctan1/x)/(x^2+1)本回答被提问者和网友采纳