高数，微分方程求通解

Question

如题所述

Answer 1

(1+y)dx +(x-1)dy=0
(1+y)dx =-(x-1)dy
- ∫dx/(x-1) = ∫dy/(1+y)
-ln|x-1| +C' =ln|1+y|
(1+y)/(x-1) =e^C'
1+y =C(x-1)
y = C(x-1) -1本回答被网友采纳