arctan[(A+B)/(A-B)]
把这个公式左边加上tan,结果等于(A+B)/(A-B),所以原题目结果就是arctan[(A+B)/(A-B)]
拓展资料
两角和正弦公式:sin(A±B)=sinAcosB±cosAsinB
两角和余弦公式:cos(A+B)=cosAcos-BcosAsinB,cos(A-B)=cosAcos+BcosAsinB
两角和正切公式:tan(A+B)=(tanA+tanB)/(1-tanAtanB),tan(A-B)=(tanA-tanB)/(1+tanAtanB)
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