@C语言大神：我代码的输入格式哪里不对？求解释、

# include<stdio.h>int main(){char system;int n,remain,result;printf("input a number:\n");scanf("%d",&n);printf("input a system:\n");scanf("%c\n",&system);//这里按理说输入的是字母，调试时不是，why? printf("the new number is:\n");//上一步到底哪里错了啊？ if(result!=0&&system=='B'){ remain=n%2; result=n/2; printf("%3d",remain); n=result;}else if(result!=0&&system=='O'){ remain=n%8; result=n/8; printf("%3d",remain); n=result;}else if(result!=0&&system=='H'){ remain=n%16; result=n/16; printf("%3d",remain); n=result;}else{ printf("wrong character or 0,input again.\n");}
getch();}

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其他回答

第1个回答推荐于2016-10-18

# include<stdio.h>
int main()
{
char system;
int n,remain,result;
printf("input a number:\n");
scanf("%d",&n);
fflush(stdin);//在输入第一个数字之后，缓存区里还有一个字符'\n'，根据scanf的机制，下一次输入的时候会对缓存区的'\n'匹配，而'\n'恰好也是一个字符，所以system='\n',这个函数是用来清除缓存区
printf("input a system:\n");
scanf("%c",&system);//对了这的“%c\n”中的\n要删去，否则在输入的时候会出问题
printf("the new number is:\n");//上一步到底哪里错了啊？
if(result!=0&&system=='B')
{ remain=n%2;
result=n/2;
printf("%3d",remain);
n=result;
}
else if(result!=0&&system=='O')
{ remain=n%8;
result=n/8;
printf("%3d",remain);
n=result;
}
else if(result!=0&&system=='H')
{ remain=n%16;
result=n/16;
printf("%3d",remain);
n=result;
}
else
{ printf("wrong character or 0,input again.\n");
}
return 0;
}追问

可是输入语句没用\n的话还是不对啊？？？

加了fflush还是没有用，为什么

追答

# include
int main()
{
char system,free;
int n,remain,result;
scanf("%d%c%c",&n,&free,&system);
printf("the new number is:\n");//上一步到底哪里错了啊？
if(result!=0&&system=='B')
{ remain=n%2;
result=n/2;
printf("%3d",remain);
n=result;
}
else if(result!=0&&system=='O')
{ remain=n%8;
result=n/8;
printf("%3d",remain);
n=result;
}
else if(result!=0&&system=='H')
{ remain=n%16;
result=n/16;
printf("%3d",remain);
n=result;
}
else
{ printf("wrong character or 0,input again.\n");
}
return 0;
}
这是满足你这道题目的输入方式