第1个回答 2013-03-28
1、输电线路的电流: I = P/V3/380 X1000 = 57.7A;
线路损耗:P1 = I^2 x r = 57.7^2 x 1 = 3333.3W = 3.3kW;
2、输电线路的电流: I2 = P/V3/10000 X1000 = 2.2A;
线路损耗:P2 = I2^2 x r = 2.2^2 x 1 = 4.84W ;
线路压降:U1 = I2 x r = 2.2 x 1 = 2.2V (与10000V比可以忽略);
3、用户得到的电压 大约为:U2 = 10000V/44 = 227.3V