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第äºä¸ªæ[A(1+β)-X](1+β)-X = A(1+β)^2-X[1+(1+β)]
第ä¸ä¸ªæ{[A(1+β)-X](1+β)-X}(1+β)-X = A(1+β)^3-X[1+(1+β)+(1+β)^2]
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A(1+β)^n-X[1+(1+β)+(1+β)^2+â¦+(1+β)^(n-1)] = A(1+β)^n-X[(1+β)^n-1]/β
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A(1+β)^m-X[(1+β)^m-1]/β = 0
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X = Aβ(1+β)^m/[(1+β)^m-1]
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