解:
原式
=[(-3mn)^2*m^3-2m^2*(3mn^2)^3*n/2]÷(-3m^2n)^2
=(9m^2n^2*m^3-2m^2*27m^3n^6*n/2)/(9m^4n^2)
=9m^5n^2/(9m^4n^2)-27m^5n^7/(9m^4n^2)
=m-3mn^5
=-3-3*(-3)*(-1)^5
=-3-9
=-12
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
祝你学习进步,更上一层楼!
不明白请及时追问,满意敬请采纳,O(∩_∩)O谢谢~~
追问=(9m^2n^2*m^3-2m^2*27m^3n^6*n/2)/(9m^4n^2)
=9m^5n^2/(9m^4n^2)-27m^5n^7/(9m^4n^2)
这两步什么意思
追答=(9m^2n^2*m^3-2m^2*27m^3n^6*n/2)/(9m^4n^2)
=(9m^2n^2*m^3-2m^2*27m^3n^6*n/2)*1/(9m^4n^2)
乘法分配率
乘进去