Point E is the midpoint of side CD in square ABCD, and BE meets diagonal AC at F.
The area of quadrilateral AFED is 45. What is the area of ABCD?
Answer:
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108
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Connect DF.
As we know, the area of â³DEF equals that of â³EFC,
and the area of â³ADF equals that of â³ABF.
SEFC:SABF=1:4 and the sum of their areas is 45.
thus, SEFC=9. SADC=54, and SABCD=108.
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