如题所述
|λI-A| =
λ-1 -2 -3
-2 λ-1 -3
-1 -1 λ-2
=
0 λ+1 1-2λ
0 -1-λ -3+(λ-1)(λ-2)
0 0 -3+(λ-1)(λ-2)+1-2λ
= λ(λ+1)(λ-5) = 0解å¾Î»=0,-1,5