甲和乙家相距1880米,两人同时从家出发相向而行,甲出发3分钟后发现忘带东西了,于是返回家取后立即启程继

1)小丁和小胖家相距1880米,两人同时从家出发相向而行,小胖出发3分钟后发现忘带东西了,于是返回家取后立即启程继续与小丁相向而行,小胖的速度是68米|分,小丁的速度是75米|分,小丁出发几分钟后两人在途中相遇?(列方程解应用题)
2)甲乙两人分别从A,B两地同时出发相向而行,行了2小时后,两人还相距40千米,又行了3小时后,两人还相距10千米(此时两人没有相遇过),A,B两地相距多少千米?(列方程解应用题)

(1)设小丁出发t分钟后两人在途中相遇
68*3+75*3*3+(68+75)*(t-9)=1880
解方程得到 t=16,即小丁出发16分钟后两人在途中相遇。
分析:小胖第一次出发三分钟走了68*3=204米,然后发现忘带东西回家,走回这204米也用了3分钟,带好东西立刻出发,走这204米又用了3分钟,所以当小胖走完这204米时,小丁已经走了9分钟,即75*9=675米,1880-675-204=1001米,走这1001米时,两人相向而行,走完这段路程所用的时间,应是这段路程的距离1001米除以两人的速度之和143米/分,即7分钟,加上刚才小丁用的9分钟,所以在小丁出发16分钟后,他们俩会在途中相遇。
(2)设AB两地相距S千米,甲的速度为X千米/小时,乙的速度为y千米/小时。
方程组为:(x+y)*2+40=S
(x+y)*3=40-10
由此解得(x+y)=10 S=60 即AB两地相距60千米。
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第1个回答  2011-03-16
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