A1Cä¸ABææçè§çæ£åå¼æ¯æ ¹å·2ã
解æï¼å 为 A1B1//ABï¼
æ以 è§B1A1Cå°±æ¯A1Cä¸ABææçè§ï¼
å æ£æ¹ä½ç棱é¿ä¸ºaï¼
æ以 B1C=(æ ¹å·2)aï¼
æ以 è§B1A1Cçæ£å=B1C/A1B1
=(æ ¹å·2)a/a
=æ ¹å·2ã
温馨提示:答案为网友推荐,仅供参考