F(x,y,z) = z^3-2xz+y = 0
z'x = -F'x/F'z =2z/ (3z^2-2x)
z''xx = 2[z'x (3z^2-2x) - z(6zz'x-2)]/(3z^2-2x)^2
= 2[-3z^2 z'x - 2xz'x + 2z]/(3z^2-2x)^2
= 2[-3z^2 2z - 2x 2z + 2z(3z^2-2x)]/(3z^2-2x)^3
= -16xz/(3z^2-2x)^3
追问哥,看不懂啊。但是额还是要采纳。比楼上那个好多了。很感谢能答题,下次用纸就更好了,谢谢。
那个z"我看不懂,咋变来的
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/dc54564e9258d109c91087cfc158ccbf6d814ddf?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
追答z''xx 是z'x对x的偏导数,详细过程见上。
本回答被提问者采纳