甲乙两组分形成的非理想溶液,在温度T时,总的蒸气压为3.52x10^4PA,气象中乙的物质量分数为0.820,同温下纯甲的饱和蒸气压为2.84x10^4pa.则溶液中甲的活度为(以甲为标准态)? 答案是0.223.求大神给讲讲过程!
a甲= p甲/p甲*
= p总[1 - x乙(g)] /P甲*
=3.52x10^4Pa / [1-0.820] /2.84x10^4pa
=0.223