用C++编写一个求N*N方阵主对角线元素之和及非主对角线元素之和的函数...答:} int main(){ int a[N][N]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16};int sum1,sum2;fun(a,&sum1,&sum2,N);cout<<"对角线元素和为:"<<sum1<<endl;cout<<"非对角线元素和为:"<<sum2<<endl;} 结果:对角线元素:1+6+11+16+4+7+10+13==68 ...
c语言求定3*3矩阵中,主副对角线上所有元素之和答:include <stdio.h> define N 3 int main() { int i,a[N][N] = {1,2,3,4,5,6,7,8,9};int major_diagonal = 0,assist_diagonal = 0;for(i = 0; i < N; ++i) { major_diagonal += a[i][i];assist_diagonal += a[i][N - 1 - i];} printf("主要对角线的和为:...
...输入一个5×5的数组,分别求其主对角线和辅对角线上元素之和...答:i][j]=n;n++;printf("%4d",a[i][j]);if(j==N-1)printf("\n");} for(i=0,j=0;i<N,j<N;i++,j++)s+=a[i][j];for(i=N-1,j=0;i>=0,j<N;i--,j++)m+=a[i][j];printf("主对角线和为:%d\n辅对角线和为:%d\n",s,m);} 自己编的 希望对你有用!
...对角线数据 输入一个5×5的数组,分别求其主对角线和辅对角线上...答:include <stdio.h> void main(){ int a[5][5]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25},i,j,sum1=0,sum2=0;for (i=0;i<5;i++){ for(j=0;j<5;j++){ if(i==j)sum1=sum1+a[i][j];if(i+j==4)sum2=sum2+a[i][...