第2个回答 2011-11-12
∵AD平分∠BAC
∴∠1=∠2
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∵∠1=∠2=∠3,△ABC中∠1+∠2+∠ABC+∠C=180°,△ABE中∠1+∠3+∠ABC+∠E=180°
∴∠C=∠E
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∵∠1=∠2,∠C=∠E,AB=AD
∴△ADC≌△ABE
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∴DC=BE本回答被提问者采纳