æ±y=(x+2)²(x-1)³çåè°åºé´
解ï¼ç±y'=2(x+2)(x-1)³+3(x+2)²(x-1)²=(x+2)(x-1)²[2(x-1)+3(x+2)]
=(x+2)(x-1)(5x+4)=0ï¼å¾ä¸ä¸ªé©»ç¹ï¼x₁=-2ï¼x₂=-4/5ï¼x₃=1ï¼
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