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f(1)=f(x)+f'(x)(1-x)+1/2*f''(x0)(1-x)^2 ,x0ä»äº1åxä¹é´
f(0)=f(x)+f'(x)(0-x)+1/2*f''(x1)(0-x)^2 ,x1ä»äº0åxä¹é´
æ以f(1)-f(0)=f'(x)+1/2*f''(x0)(1-x)^2-1/2*f''(x1) x^2
æ以|f'ï¼xï¼|â¤|f(1)|+|f(0)|+1/2*|f''(x1)|x^2+1/2*|f''(x0)|(1-x)^2â¤2a+b/2[x^2+(1-x)^2]â¤2a+b/2
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