解ï¼å¨CDä¸æ¾ç¹Eï¼ä½¿CE=ACï¼è¿æ¥AE
æ以è§AEC=EAC
å 为è§ACB=è§AEC+EAC
æ以è§ACB=2è§AEC
å 为è§ACB=2è§B
æ以è§AEC=è§B
æ以AE=AB
å 为è§FAC=2FAD=è§ACB+è§B
æ以2è§FAD=3è§Bï¼è§FAD=è§B+1/2è§B
å 为è§FAD=è§B+è§D
æ以è§D=1/2è§B=1/2è§AEC
æ以è§AEC=2è§D
å 为è§AEC=è§D+è§DAE
æ以è§D=DAE
æ以AE=DE
å 为AB=AEï¼DE=CD-CEï¼CE=AC
æ以AB=CD-AC
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